[Dec 02, 2024] 1z0-071 Exam Dumps – Try Best 1z0-071 Exam Questions – PassLeaderVCE [Q175-Q190]

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[Dec 02, 2024] 1z0-071 Exam Dumps – Try Best 1z0-071 Exam Questions – PassLeaderVCE

Verified 1z0-071 exam dumps Q&As with Correct 323 Questions and Answers

Oracle 1z0-071 exam is intended for professionals who want to improve their skills in database management, database design, and application development. It is ideal for database administrators, developers, analysts, and other IT professionals who want to gain expertise in Oracle database and SQL programming. 1z0-071 exam tests the candidate’s knowledge of SQL concepts and their ability to apply them to real-world scenarios.

Q175. Examine the description of the EMPLOYEES table:

Which statement increases each employee's SALARY by the minimum SALARY for their DEPARTM ENT_ID?

UPDATE employees e1
SET salary =(SELECT e2. salary + MIN(e2.salary)
FROM employees e2
WHERE e1.department_ id = e2. department_id GROUP BY e2. department_id) ;

UPDATE employees e1
SET salary = salary +
(SELECT MIN(e1. salary)
FROM employees e2
WHERE e1.department_id = e2 .department_id);

UPDATE employees e1
SET salary = salary+(SELECT MIN (salary)
FROM employees e2) ;

UPDATE employees e1
SET salary=
(SELECT e1.salary + MIN(e2.salary)
FROM employees e2
WHERE e1. department_ id = e2.department_id);

The correct statement to increase each employee’s salary by the minimum salary for their department is:
D: This option correctly increases each employee’s salary by the minimum salary in their department. The subquery calculates the minimum salary for the department of the current row being updated (e1) in the outer UPDATE statement. The subquery does not use GROUP BY since it returns a single value – the minimum salary for the matching department.A, B, and C are incorrect. Specifically:
* A uses a subquery with an aggregate function combined with GROUP BY, which is not needed and will result in an error.
* B incorrectly references MIN(e1.salary) within the subquery, which is incorrect since e1 is the alias for the outer query’s table and should not be used within the subquery.
* C sets the salary to itself plus the minimum salary across all employees, not filtered by the department.
References:
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): “UPDATE”

Q176. Which two statements are true about sequences crated in a single instance Oracle database?

The numbers generated by an explicitly defined sequence can only be used to insert data in one table.

DELETE <sequencename> would remove a sequence from the database.

CURRVAL is used to refer to the most recent sequence number that has been generated for a particular sequence.

When the MAXVALUE limit for a sequence is reached, it can be increased by using the ALTER SEQUENCE statement.

When the database instance shuts down abnormally, sequence numbers that have been cached but not used are available again when the instance is restarted.

Q177. Which statement is true regarding the USINGclause in table joins? (Choose two.)

It can be used to join a maximum of three tables.

It can be used to access data from tables through equijoins as well as nonequijoins.

It can be used to join tables that have columns with the same name and compatible data types.

It can be used to restrict the number of columns used in a NATURALjoin.

Explanation

Q178. Which two are true about queries using set operators (UNION, UNION ALL, INTERSECT and MINUS)?

There must be an equal number of columns in each SELECT list.

The name of each column in the first SELECT list must match the name of the corresponding column in each subsequent SELECT list.

Each SELECT statement in the query can have an ORDER BY clause.

None of the set operators can be used when selecting CLOB columns.

The FOR UPDATE clause cannot be specified.

Q179. Which three statements are true about sequences in a single instance Oracle database? (Choose three.)

A sequence can issue duplicate values

A sequence’s unallocated cached value are lost if the instance shuts down

Sequences can always have gaps

Two or more tables cannot have keys generated from the same sequence

A sequence can only be dropped by a DBA

A sequence number that was allocated can be rolled back if a transaction fails

Explanation/Reference: https://docs.oracle.com/cd/B19306_01/server.102/b14200/statements_6015.htm

Q180. The user SCOTT who is the owner of ORDERS and ORDER_ITEMS tables issues this GRANT command:
GRANT ALL
ON orders, order_items
TO PUBLIC;
What must be done to fix the statement?

PUBLIC should be replaced with specific usernames.

ALL should be replaced with a list of specific privileges.

WITH GRANT OPTION should be added to the statement.

Separate GRANT statements are required for the ORDERS and ORDER_ITEMS tables.

References:
http://docs.oracle.com/javadb/10.8.3.0/ref/rrefsqljgrant.html

Q181. The following are the steps for a correlated subquery, listed in random order:
1) The WHERE clause of the outer query is evaluated.
2) The candidate row is fetched from the table specified in the outer query.
3) The procedure is repeated for the subsequent rows of the table, till all the rows are processed.
4) Rows are returned by the inner query, after being evaluated with the value from the candidate row in the outer query. Identify the option that contains the steps in the correct sequence in which the Oracle server evaluates a correlated subquery.

4,2,1,3

4,1,2,3

2,4,1,3

2,1,4,3

Q182. Evaluate the following SQL statement:
SQL> select cust_id, cust_last_name “Last name”
FROM customers
WHERE country_id = 10
UNION
SELECT cust_id CUST_NO, cust_last_name
FROM customers
WHERE country_id = 30
Identify three ORDER BY clauses either one of which can complete the query. (Choose three.)

ORDER BY “Last name”

ORDER BY 2, cust_id

ORDER BY CUST_NO

ORDER BY 2,1

ORDER BY “CUST_NO”

Using the ORDER BY Clause in Set Operations
-The ORDER BY clause can appear only once at the end of the compound query.
-Component queries cannot have individual ORDER BY clauses.
-The ORDER BY clause recognizes only the columns of the first SELECT query.
-By default, the first column of the first SELECT query is used to sort the output in an ascending order.

Q183. Which two statements are true regarding the WHERE and HAVING clauses in a SELECT statement? (Choose two.)

The WHERE and HAVING clauses can be used in the same statement only if they are applied to different columns in the table.

The aggregate functions and columns used in the HAVING clause must be specified in the SELECT list of the query.

The WHERE clause can be used to exclude rows after dividing them into groups.

The HAVING clause can be used with aggregate functions in subqueries.

The WHERE clause can be used to exclude rows before dividing them into groups.

Q184. Which three statements are correct regarding indexes? (Choose three.)

A non-deferrable PRIMARY KEY or UNIQUE KEY constraint in a table automatically attempts to create a unique index.

Indexes should be created on columns that are frequently referenced as part of any expression.

When a table is dropped, corresponding indexes are automatically dropped.

For each DML operation performed on a table, the corresponding indexes are automatically updated if required.

References:
http://viralpatel.net/blogs/understanding-primary-keypk-constraint-in-oracle/

Q185. Refer to the exhibit.

Which two queries will result in an error?

SELECT FIRST_NAME LAST_NAME FROM EMPLOYEES;

SELECT FIRST_NAME,LAST_NAME FROM EMPLOYEES;

SELECT LAST_NAME,12 * SALARY AS ANNUAL_SALARY
FROM EMPLOYEES
WHERE ANNUAL_SALARY > 100000
ORDER BY 12 * SALARY ;

SELECT LAST_NAME,12 * SALARY AS ANNUAL_SALARY
FROM EMPLOYEES
WHERE 12 * SALARY > 100000
ORDER BY ANNUAL_SALARY;

SELECT LAST_NAME,12 * SALARY AS ANNUAL_SALARY
FROM EMPLOYEES
WHERE 12 * SALARY > 100000
ORDER BY 12 * SALARY;

SELECT LAST_NAME,12 * SALARY AS ANNUAL_SALARY
FROM EMPLOYEES
WHERE ANNUAL_SALARY > 100000
ORDER BY ANNUAL_SALARY;

Q186. Examine this SQL statement:

Identify three order by clauses, any one of which can complete the query successfully.

ORDER BY CUST_NO

ORDER BY 2, 1

ORDER BY 2, cust_id

ORDER BY “Last Name”

ORDER BY “CUST NO”

Q187. Examine the description of the CUSTOMERS table:

You want to display details of all customers who reside in cities starting with the letter D followed by at least two character.
Which query can be used?

SELECT * FROM customers WHERE city =’D_%’;

SELECT * FROM customers WHERE city =’%D_’;

SELECT * FROM customers WHERE city LIKE’D %’;

SELECT * FROM customers WHERE city LIKE’D_’;

Q188. Examine the description of the ENPLYEES table:

Which two queries return all rows for employees whose salary is greater than the average salary in their department?

SELECT “
FROM employees
WHERE salary > ANY
SELECT AVG (salary)
EROM employees
GROUP BY department_ id);

SELECT
FROM employees
WHERE salary > AVG (salary) OVER (PARTITION BY department _ id);

SELECT”
FROM employees e1
WHERE salary >!
SELECT AVG (salary)
FROM employees e2
WHERE e1. Department _id = e2, department_ id

SELECT.
FROM
SELECT e.”, AVG (salary) OVER (PARTITION BY department id) avg_ sal
FROM employees e
WHERE salary > avg_ sal;

SELECT”
FROM employees
WHERE salary >
( SELECT AVG
(salary) FROM
employees
GROUP BY department _ id

Q189. You want to display the date for the first Monday of the next month and issue the following command:

What is the outcome?

In generates an error because rrrrshould be replaced by rrin the format string.

It executes successfully but does not return the correct result.

It executes successfully and returns the correct result.

In generates an error because TO_CHARshould be replaced with TO_DATE.

In generates an error because fmand double quotation marks should not be used in the format string.

Q190. View the Exhibit and examine the structure of the PRODUCTS table. (Choose the best answer.) You must display the category with the maximum number of items.
You issue this query:
SQL > SELECT COUNT(*), prod_category_id
FROM products
GROUP BY prod_category_id
HAVING COUNT(*) = (SELECT MAX(COUNT(*)) FROM porducts);
What is the result?

It generates an error because = is not valid and should be replaced by the IN operator.

It executes successfully but does not give the correct output.

It executes successfully and gives the correct output.

It generate an error because the subquery does not have a GROUP BY clause.

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Oracle 1z0-071 certification exam covers various topics, including SQL fundamentals, data retrieval using SQL select statements, data manipulation using SQL DML statements, database object creation and management, and control statements. 1z0-071 exam is designed to challenge the candidate’s understanding of SQL and its use in managing and manipulating data in an Oracle database environment. 1z0-071 exam requires the candidate to have a thorough understanding of SQL concepts and their practical application in real-world scenarios.

Oracle 1z0-071 Test Engine PDF – All Free Dumps: https://www.passleadervce.com/Oracle-PL-SQL-Developer-Certified-Associate/reliable-1z0-071-exam-learning-guide.html

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