A Fully Updated 2025 1z0-071 Exam Dumps – PDF Questions and Testing Engine [Q53-Q71]

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A Fully Updated 2025 1z0-071 Exam Dumps – PDF Questions and Testing Engine

Easy Success Oracle 1z0-071 Exam in First Try

To prepare for the Oracle 1z0-071 certification exam, candidates can take advantage of various training resources, including online courses, instructor-led training, and study guides. They can also practice their SQL skills by working on real-world projects or using simulation tools. A passing score on the Oracle 1z0-071 certification exam demonstrates a candidate’s proficiency in SQL development and database management and validates their skills to potential employers.

QUESTION 53
Examine this statement:

What is returned upon execution?

1 row

an error

0 rows

2 rows

QUESTION 54
In which normal form is a table, if it has no multi-valued attributes and no partial dependencies?

second normal form

first normal form

third normal form

fourth normal form

QUESTION 55
An Oracle database server session has an uncommitted transaction in progress which updated 5000 rows in a table.
In which three situations does the transact ion complete thereby committing the updates?

When the session logs out is successfully

When a DBA issues a successful SHUTDOWN IMMEDIATE statement and the user then issues a COMMIT

When a CREATE INDEX statement is executed successfully in same session

When a COMMIT statement is issued by the same user from another session in the same database instance

When a CREATE TABLE AS SELECT statement is executed unsuccessfully in the same session

When a DBA issues a successful SHUTDOWN TRANSACTIONAL statement and the user, then issues a COMMIT

QUESTION 56
Which two statements are true regarding the USING and ON clauses in table joins?

Both USING and ON clauses can be used for equijoins and nonequijoins.

A maximum of one pair of columns can be joined between two tables using the ON clause.

The ON clause can be used to join tables on columns that have different names but compatible data types.

The WHERE clause can be used to apply additional conditions in SELECT statements containing the ON or the USING clause.

QUESTION 57
Which two are true about queries using set operators such as UNION?

An expression in the first SELECT list must have a column alias for the expression

CHAR columns of different lengths used with a set operator retum a vAacsua mhtoe e equals the longest CHAR value.

Queries using set operators do not perform implicit conversion across data type groups (e.g. character, numeric)

In a query containing multiple set operators INTERSECT always takes precedence over UNION and UNION ALL

All set operators are valid on columns all data types.

QUESTION 58
Which three statements are true about multiple row subqueries?

They can contain GROUP BY clauses.

They can return multiple columns.

Two or more values are always returned from the subquery.

They can contain HAVINGclauses.

They cannot contain a subquery.

QUESTION 59
Examine these statements and results:
SQL> SELECT COUNT(*) FROM emp
COUNT(*)
———————
14
sQL> CREATE GLOBAL TEMPORARY TABLE t emp As SELECT * FROM emp;
Table created
SQL> INSERT INTo temp SELECT * FROM emp;
14 rows created
SQL> COMMIT:
Commit complete*
SQL> INSERT INTo temp SELECT * EROM emp;
14. rows created
SQL> SELECT COUNT(*) FROM t emp
How many rows are retrieved by the last query?

QUESTION 60
Examine the data in the COLORS table:

Examine the data in the BRICKS table:

Which two queries return all the rows from COLORS?

AIl conditions evaluated using DECODE can also be evaluated using CASE.

All conditions evaluated using CASE can also be evaluated using DECODE.

CASE is a function and DECODE is not.

DECODE is a function and CASE is not.

Neither CASE nor DECODE is a function.

Both CASE and DECODE are functions.

QUESTION 61
View the Exhibit and examine the structure of the PRODUCT table.

Which two tasks would require subqueries? (Choose two.)

display all products whose PROD_MIN_PRICE is more than the average PROD_LIST_PRICE of all products, and whose status is orderable

display the total number of products supplied by supplier 102 and have product status as ‘OBSOLETE’

display the number of products whose PROD_LIST_PRICE is more than the average PROD_LIST_PRICE.

display suppliers whose PROD_LIST_PRICE is less than 1000

display the minimum PROD_LIST_PRICE for each product status

QUESTION 62
Examine this partial statement:
SELECT ename, sal,comm FROM emp
Now examine this output:

WHICH ORDER BY clause will generate the displayed output?

ORDER BY NVL(enam,0) DESC, ename

ORDER BY NVL(comm,0) ASC NULLS FIRST, ename

ORDER BY NVL(comm,0) ASC NULLS LAST, ename

ORDER BY comm DESC NULLS LAST, ename

QUESTION 63
You create a table by using this command:
CREATE TABLE rate_list (rate NUMBER(6,2));
Which two are true about executing statements?

INSERT INTO rate_list VALUES (-.9) inserts the value as -.9.

INSERT INTO rate_list VALUES (0.999) produces an error.

INSERT INTO rate_list VALUES (-10) produces an error.

INSERT INTO rate_list VALUES (87654. 556) inserts the value as 87654.6.

INSERT INTO rate_list VALUES (0.551) inserts the value as .55.

INSERT INTO rate_list VALUES (-99.99) inserts the value as 99.99.

QUESTION 64
View the exhibit and examine the data in ORDERS_MASTER and MONTHLY_ORDERS tables.
ORDERS_MASTER
ORDER_ID
ORDER_TOTAL
1
1000
2
2000
3
3000
4
MONTHLY_ORDERS
ORDER_ID
ORDER_TOTAL
2
2500
3
Evaluate the following MERGE statement:
MERGE_INTO orders_master o
USING monthly_orders m
ON (o.order_id = m.order_id)
WHEN MATCHED THEN
UPDATE SET o.order_total = m.order_total
DELETE WHERE (m.order_total IS NULL)
WHEN NOT MATCHED THEN
INSERT VALUES (m.order_id, m.order_total)
What would be the outcome of the above statement?

The ORDERS_MASTER table would contain the ORDER_IDs 1, 2, 3 and 4.

The ORDERS_MASTER table would contain the ORDER_IDs 1, 2 and 4.

The ORDERS_MASTER table would contain the ORDER_IDs 1, 2 and 3.

The ORDERS_MASTER table would contain the ORDER_IDs 1 and 2.

QUESTION 65
Examine the business rule:
Each student can work on multiple projects and each project can have multiple students.
You need to design an Entity Relationship Model (ERD) for optimal data storage and allow for generating reports in this format:
STUDENT_ID FIRST_NAME LAST_NAME PROJECT_ID PROJECT_NAME PROJECT_TASK
Which two statements are true in this scenario?

The ERD must have a 1:M relationship between the STUDENTSand PROJECTSentities.

The ERD must have a M:M relationship between the STUDENTSand PROJECTSentities that must be resolved into 1:M relationships.

STUDENT_IDmust be the primary key in the STUDENTSentity and foreign key in the PROJECTSentity.

PROJECT_IDmust be the primary key in the PROJECTSentity and foreign key in the STUDENTSentity.

An associative table must be created with a composite key of STUDENT_ID and PROJECT_ID, which is the foreign key linked to the STUDENTS and PROJECTS entities.

QUESTION 66
You want to write a query that prompts for two column names and the WHERE condition each time It is executed in a session but only prompts for the table name the first time it is executed. The variables used in your query are never undefined in your session . Which query can be used?

SELECT &col1, &col2
FROM &&table
WHERE &condition;

SELECT &col1, &col2
FROM “&table”
WHERE &condition;

SELECT &&col1,&&col2
FROM &table
WHERE &&condition= &&cond;

SELECT’&co11′,’&&co12′
FROM &table
WHERE’&&condition’ =’&cond’;

SELECT&&col1, &&col2
FROM &table
WHERE &&condition;

QUESTION 67
Which statement executes successfully?

SELECT TO_DATE(TO_NUMBER(INTERVATL ‘800’ SECOND)) FROM DUAL;

SELECT TO_NUMBER(INTERVAL’800′ SECOND, ‘HH24:MM’) FROM DUAL;

SELECT TO_DATE(INTERVAL ‘800’ SECOND,’HH24:MM’) FROM DUAL;

SELECT TO_NUWBER(TO_DATE(INTERVAL ‘800’ SECOND)) FROM DUAL;

SELECT TO_CHAR(INTERVAL ‘800’ SECOND, ‘HH24:MM’) FROM DUAL;

QUESTION 68
View the Exhibit and examine the descriptions of the DEPT and LOCATIOMS tables.

You want to update the CITY column of the DEPT table for all the rows with the corresponding value in the CITY column of the LOCATIONS table for each department.
Which SQL statement would you execute to accomplish the task?

UPDATE dept d
SET city = ANY (SELECT city FROM locations l);

UPDATE dept d
SET city = (SELECT city FROM locations l)
WHERE d.location_id = l.location_id;

UPDATE dept d
SET city = (SELECT city
FROM locations l
WHERE d.location_id = l.location_id);

UPDATE dept d
SET city = ALL (SELECT city
FROM locations l
WHERE d.location_id = l.location_id);

QUESTION 69
View the Exhibit and examine the details of PRODUCT_INFORMATION table.

You have the requirement to display PRODUCT_NAME from the table where the CATEGORY_ID column has values 12 or 13, and the SUPPLIER_ID column has the value 102088. You executed the following SQL statement:
SELECT product_name
FROM product_information
WHERE (category_id = 12 AND category_id = 13) AND supplier_id = 102088;
Which statement is true regarding the execution of the query?

It would not execute because the same column has been used in both sides of the AND logical operator to form the condition.

It would not execute because the entire WHERE clause condition is not enclosed within the parentheses.

It would execute and the output would display the desired result.

It would execute but the output would return no rows.

QUESTION 70
You must create a table EMPLOYEES in which the values in the columns
EMPLOYEES_ID and LOGIN_ID must be unique and not null. (Choose two.)
Which two SQL statements would create the required table?

CREATE TABLE employees(employee_id NUMBER,Login_id
NUMBER,Employee_name VARCHAR2(100),Hire_date DATE,CONSTRAINT
emp_id_ukUNIQUE (employee_id, login_id));

CREATE TABLE employees(employee_id NUMBER,login_id
NUMBER,employee_name VARCHAR2(25),hire_date DATE,CONSTRAINT emp_id_pk
PRIMARY KEY (employee_id, login_id));

CREATE TABLE employees(employee_id NUMBER CONSTRAINT emp_id_pk
PRIMARY KEY, Login_id NUMBER UNIQUE, Employee_name VARCHAR2(25),Hire_date DATE);

CREATE TABLE employees(employee_id NUMBER,Login_id
NUMBER,Employee_name VARCHAR2(100),Hire_date DATE,CONSTRAINT emp_id_uk
UNIQUE (employee_id, login_id);CONSTRAINT emp_id_nn NOT NULL (employee_id, login_id));

CREATE TABLE employees(employee_id NUMBER CONSTRAINT emp_id_nn NOT
NULL, Login_id NUMBER CONSTRAINT login_id_nn NOT NULL,Employee_name
VARCHAR2(100),Hire_date DATE,CONSTRAINT emp_id_ukUNIQUE (employee_id,
login_id));

QUESTION 71
Examine the description of the CUSTOMERS table:

You need to display last names and credit limits of all customers whose last name starts with A or B In lower or upper case, and whose credit limit is below 1000.
Examine this partial query:
SELECT cust_last_nare, cust_credit_limit FROM customers
Which two WHERE conditions give the required result?

WHERE UPPER(cust_last_name) IN (‘A%’, ‘B%’) AND cust_credit_limit < 1000:

WHERE (INITCAP(cust_last_name) LIKE ‘A%’ OR ITITCAP(cust_last_name) LIKE ‘B%’) AND cust_credit_limit < 1000

WHERE UPPER(cust_last_name) BETWEEN UPPER(‘A%’ AND ‘B%’) AND ROUND(cust_credit_limit) < 1000;

WHERE (UPPER(cust_last_name) LIKE ‘A%’ OR UPPER(cust_last_name) LIKE ‘B%’) AND ROUND(cust_credit_limit) < 1000;

WHERE (UPPER(cust_last_name) like INITCAP (‘A’) OR UPPER(cust_last_name) like INITCAP(‘B’)) AND ROUND(cust_credit_limit) < ROUND(1000) ;

Oracle 1z1-071 exam consists of 73 multiple-choice questions, which must be completed within 100 minutes. 1z0-071 exam covers a range of topics, including SQL functions, data manipulation, data retrieval, and data control. 1z0-071 exam also covers the basics of Oracle Database 12c, including its architecture, data types, and database objects.

1z0-071 Study Material, Preparation Guide and PDF Download: https://www.passleadervce.com/Oracle-PL-SQL-Developer-Certified-Associate/reliable-1z0-071-exam-learning-guide.html